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Delectation Delicatessen

 Essay upon Delectation Delicatessen

Homework Difficulty Set #1

Delectation Delicatessen

Problem a)

Answer:

Delectation wants to decide the number of Fish-n-Fowl and Surf-n-Turf sandwiches it may make everyday to maximize the deli's earnings in USD$. The decision parameters are just how many devices of Fish-n-Fowl and Surf-n-Turf sandwiches Delectation should generate each day. F= units of Fish-n-Fowl sandwiches Delectation should make each day. S= units of Surf-n-Turf sandwiches Delectation should make each day. The aim function: maxmize F times 5. 40 + T x six. 95

The Constraints:

0. twenty-five x Farreneheit + 0. 25 times S< =200| Tuna seafood salad | Pound

0. 5 x F < =260| Chopped up turkey| Pound

0. 40 x S < =60| Sliced roast beef| Pound

2 back button F + 1 times S< =1500| Rye bread| Slice

one particular x Farrenheit + 1 x S< =800| Pumpernickel break| Cut

F and S> =0; | В | F and S are both integersВ | В

Problem b)

Answer:

Realization: Delectation should produce 520 units of Fish-n-Fowl and 150 units of Surf-n-Turf sandwiches Delectation each day to generate $3, 902. 50 income. Power Prepare problem

Issue a)

Response:

The administration of OMPIC wants to identify the mix of coals that may maximize the quantity of power made per hour. The decision variables will be how a large number of tons of Hard Coal and Soft Coal should be utilized to maximize the amount of power in BTU per hour while making sure that you comply the with the emission requirements. H= a great deal of Hard Coal should be utilized per hour. S= tons of Soft Coal should be used each hour. The objective function: maximize L x twenty four, 000 & S by 20, 500

The Limitations:

SO2 emission-H x 1500 +S x five-hundred < =0 PPM Particulate emission They would x 0. 65 + S by 1 . 05 < = 12 kilogram Pulverizer potential H back button 24+S times 16< sama dengan 384 ton/hour Conveyor capability H+S< sama dengan 20 ton/hour No unfavorable input They would and S> =0 Trouble b)

Answer:

The objective function: assuming unit price =1, minimize They would x 1 . 15 +S x one particular H= tons of Hard Fossil fuel should be employed per hour. S= tons of Very soft Coal ought to be used per hour. The Constraints:

High temperature output H x twenty four, 000+S times 20, 000=390, 000 BTU/hour SO2 emission-H x 1500 +S back button 500 < =0 PPM Particulate emission H by 0. sixty-five + S x 1 . 05 < = doze kg/hour Pulverizer capacity H x 24+S x 16< = 384 ton/hour Conveyor capacity H+S< = 20 ton/hour Not any negative type H and S> =0 Gaussian Laminates company

Issue a) burning off 100 products of development capacity by plant A Answer:

It will eventually increase the total operating price by $25 assuming other folks remain continuous. Shadow value of " from grow A production qty” can be -$0. twenty-five. So lowering product simply by 100 models will increase expense by 100 x $0. 25 = $25. The production and delivery plan will change. Plan A will now develop 1900 devices or 90 units fewer. Plant A will send 1000 products or 95 units fewer to location 1 . Flower B is going to produce 1900 units, 100 units more. Plan M will deliver 1100...

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