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Me pertaining to Mcgill

 Me pertaining to Mcgill Article

Chun Set up Liu

260239061

CHAPTER some

Question 1

Q=300S+200U-0. 2S^2-0. 3U^2

Ps=10

Pu=5

MPs=300-0. 3

MPu=200-0. 6U

MPs/Ps=MPu/Pu

(300-0. 4S)/10=(200-0. 6U)/5

300-0. 4S=400-1. 2U

1 . 2U=0. 4S+100

U=0. 33S+83. 33

If S= 4 hundred, then U=0. 33(400)+83. 33=216. 66 If we want to maximize earnings and use 400 hours of qualified labor, we might need 216. 66 hours of not skilled labor. We would not comply with Elwyn's suggestion. 10S+5U=5000 U=1000-2S

U=0. 33S+83. 33

1000-2S=0. 33S+83. thirty-three

2 . 33S=916. 67

S=393. 42

U=1000-2(393. 42)=213. 16

MR(MPU)=MEU 10(200-0. 6U)=5

200-0. 6U=0. 5

U=(200-0. 5)/(0. 6)

U=332. 5

Query 6

AP= total milk/total materials = (5917+7250+8379+9371)/(1200+1800+2400+3000) = a few. 68 pounds of milk per pound of materials

MEGA-PIXEL between 1200 and toll free = (7250-5917)/(1800-1200) = 2 . 22 MEGAPIXEL between 1850 and 2400 = (8379-7250)/(2400-1800) = 1 ) 88 MP between 2400 and 3 thousands = (9371-8379)/(3000-2400) = 1 ) 65

Yes it does. Marginal product decreases because units of grain maximize. CHAPTER five Question 3

TC= TVC+TFC TC=100Q+5000

Earnings = TR – TC

10000=300Q – 100Q+5000

5000 = 200Q

Q=25

10000=350Q-100Q+5000 5000=250Q

Q=20

10000=350Q-85Q+5000 5000=265Q

Q=18. 86

Around 19 units.

Question four

Once Q can be 50, C=16. 68+0. 125(50)+0. 00439(50)^2

C=33. 905

When ever Q is 51,

C=16. 68+0. 125(51)+0. 00439(51)^2

C=34. 473

Difference of an increase of 0. 568

The administrator can realize that the limited cost is great and can estimate the little cost. It will help him increase profits having a bit more computations and info. MC=0. 125+0. 00878Q

This can help managers maximize revenue if they will make MC=MR. Question 5

Outcome Total Expense TFC TVC AFC AVC

0 50 55 0 - -

1 seventy five 50 25 50 twenty-five

a couple of 100 55 50 25 25

3 one hundred twenty 50 70 16. sixty six 23. 33

5 135 50 85 12. 5 twenty-one. 25

5 one hundred and fifty 50 90 10 20

6th 190 60 140 eight. 33 twenty-three. 33

7 260 50 210 7. 13 30

Question 6

TC=Q*AC TC=3Q+4Q^2

No it doesn't because once Q=0, TC = zero also. Because of this all costs come from changing costs. MC=3+8Q

TR=3Q

MR=3

MC=MR

3+8Q=3

Q=0

The business is producing a loss because all their profit is usually maximized when Q=0. The greater they sell and make, the more they shed. TC=3Q+4Q^2 MC=3+8Q

Problem 9

MC=50-20Q+3Q^2 Will probably be at a minimum when the derivative of MC = 0 -20+6Q=0

Q=20/6=3. 33

AVC=TVC/Q AVC=50-10Q+Q^2

Will be at a minimum if the derivative of AVC = 0

-10+2Q=0

Q=5

AVC=50-10(5)+5^2 =25

MC=50-20(5)+3(5^2)

=25

Question 10

TVC=$14 TFC=$300, 000

For 10000 units, will definitely cost

TC=TVC+TFC

=14*10000+300000

=440000

TR=25*10000

=250000

Profit=250000-440000

=-190000

Lose 190000$ and so, they should not really introduce the modern product. Profit = 200000-440000 =--240000

Lose 240000$ and so, they must not bring in the new product. Profit sama dengan 150000-440000 =-290000

Lose 290000$ and so, they need to not expose the new item. The bare minimum price they should charge is definitely 44$ per unit in the event that they can promote 10000 units. They would generate 0$ revenue in this case. Problem 11 Degree=(23000+11000-30000)/30000=0. 133

When ever production establishments are used to create one merchandise, sometimes another product is likewise created at the same time. If this newly made product were to be used for the creation of other goods, these other products would be cheaper to make. Problem 12

AVC=$24 TVC=24/Q

24$=40%

Revenue + FC = 60 per cent of desk

(24/4)*10=60$ per stand

Recently, sold 10000 tables. if perhaps price boost by 10%, we will have to sell 10000/1. 1=9090. 91

About 9091 furniture.

((241. 08)/410)/60=1. '08 9090. 91/1. 08=8417. 51

Around 8418 dining tables

SECTION 6

Question one particular

AC=(250000/Q)+150+3Q MAC=(-25000/Q^2)+3=0...

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